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Assets/trCRM/upgradeRes4Dev/priority/lua/toolkit/BitUtl.lua

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+--与   同为1，则为1
+--或   有一个为1，则为1
+--非   true为 false，其余为true
+--异或 相同为0，不同为1
+
+BitUtl = {}
+local __andBit = function(left, right) --与
+    return (left == 1 and right == 1) and 1 or 0
+end
+
+local __orBit = function(left, right) --或
+    return (left == 1 or right == 1) and 1 or 0
+end
+
+local __xorBit = function(left, right) --异或
+    return (left + right) == 1 and 1 or 0
+end
+
+local __base = function(left, right, op) --对每一位进行op运算，然后将值返回
+    if left < right then
+        left, right = right, left
+    end
+    local res = 0
+    local shift = 1
+    while left ~= 0 do
+        local ra = left % 2 --取得每一位(最右边)
+        local rb = right % 2
+        res = shift * op(ra, rb) + res
+        shift = shift * 2
+        left = math.modf(left / 2) --右移
+        right = math.modf(right / 2)
+    end
+    return res
+end
+
+---@public 与
+function BitUtl.andOp(left, right)
+    return __base(left, right, __andBit)
+end
+
+---@public 或
+function BitUtl.orOp(left, right)
+    return __base(left, right, __orBit)
+end
+
+---@public 异或
+function BitUtl.xorOp(left, right)
+    return __base(left, right, __xorBit)
+end
+
+---@public 非
+function BitUtl.notOp(left)
+    return left > 0 and -(left + 1) or -left - 1
+end
+
+---@public left左移num位
+function BitUtl.lShiftOp(left, num)
+    return left * (2 ^ num)
+end
+
+---@public right右移num位
+function BitUtl.rShiftOp(left, num)
+    return math.floor(left / (2 ^ num))
+end
+return BitUtl